Write a function seqsum() in c++ with two arguments, double x and int n. The function should return a value of type double and it should find the sum of the following series:
1+ x/(2!) + x^2/(4!) +........+ x^n/((2n)!)
1
Expert's answer
2013-06-25T09:55:25-0400
#include <iostream> #include <cmath>
using namespace std;
long factorial(int n) { long result = 1; while (n) result *= n--; return result; }
double seqsum(double x, int n) { double result = 1.0; for (int k = 1; k <= n; k++) result += pow(x, k) / factorial(2 * k); return result; }
int main() { cout << "x = 1:" << endl; for (int n = 0; n < 5; n++) cout << " n = " << n << " " << seqsum(1, n) << endl; return 0; }
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