Answer to Question #323168 in C++ for Bea

Question

Write one dimensional array java program that ask to the user to enter the array

size and reads n integers, compute their average, and find out how many

numbers are above the average. Your program first enter the array size and reads

the numbers and computes their average, then compares each number with the

average to determine whether it is above the average.

Sample Input/Output:

How many numbers do you have?6

Enter a value for array [1]:100

Enter a value for array [2]:10

Enter a value for array [3]:1000

Enter a value for array [4]: 500

Enter a value for array [5]: 200

Enter a value for array [6]: 77

List of elements: 100 10 1000 500 200 77

The sum of the 6 elements: 1887.00

The average of the 5 elements: 314.50

Numbers above average: 4

Answer 1

#include<iostream>
#include <iomanip>
using namespace std;




int main()
{
	int n;
	cout<<"How many numbers do you have? ";
	cin>>n;
	int* numbers=new int[n];
	for(int i=0;i<n;i++){
		cout<<"Enter a value for array ["<<(i+1)<<"]: ";
		cin>>numbers[i];
	}
	int sum=0;
	int numbersAboveAverage=0;
	cout<<"\nList of elements: ";
	for(int i=0;i<n;i++){
		cout<<numbers[i]<<" ";
		sum+=numbers[i];
	}
	float average=(float)sum/(float)n;
	for(int i=0;i<n;i++){
		if(numbers[i]>average){
			numbersAboveAverage++;
		}
	}
	cout<<fixed<<"\nThe sum of the 6 elements: "<<setprecision(2)<<(float)sum<<"\n";
	cout<<"The average of the 5 elements: "<<setprecision(2)<<average<<"\n";
	cout<<"Numbers above average: "<<numbersAboveAverage<<"\n\n";
	delete numbers;


	system("pause");
	return 0;
}