Answer to Question #320794 in C++ for john

Question #320794

Search and Rescue



by CodeChum Admin



Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.




Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".




Start coding now!



Input



The first line contains the size of the array. The next lines contain the integers. The last line contains an integer to be searched.



5 3 21 2 5 23 2



Output



A line containing a string.



Present




1
Expert's answer
2022-03-30T14:10:20-0400
#include<iostream>

using namespace std;

int main()
{
	int sz, search;
	cout << "Please, enter a random integer: ";
	cin >> sz;
	int* arr = new int[sz];
	cout << "Please, enter values for array: ";
	for (int i= 0; i < sz; i++)
	{
		cin >> arr[i];
	}
	cout << "Please, enter a value for search in array: ";
	cin >> search;
	bool searched = false;
	for (int i = 0; i < sz; i++)
	{
		if (arr[i] == search)
		{
			searched = true;
			break;
		}
	}
	if (searched)
		cout << "Present";
	else
		cout << "None";
}

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