Answer to Question #315063 in C++ for Secret Agent

Question

Search and Rescue

by CodeChum Admin

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

Start coding now!

Input

The first line contains the size of the array.

The next lines contain the integers.

The last line contains an integer to be searched.

5
3
21
2
5
23
2

Output

A line containing a string.

Present

Answer 1

#include <iostream>
#include <array>
using namespace std;

int main() {
    size_t n;
    int* A;

    cin >> n;
    A = new int[n];

    for (int i=0; i<n; i++) {
        cin >> A[i];
    }

    int num;
    bool find=false;
    cin >> num;

    for (int i=0; i<n; i++) {
        if (A[i] == num) {
            find = true;
            break;
        }
    }

    if (find) {
        cout << "Present";
    }
    else {
        cout << "None";
    }
    delete [] A;

    return 0;
}