Answer to Question #312422 in C++ for mmmm

Question

As a form of quality control, the Pancake Kitchen has recorded, on a Pancake file, two measurements for each of its pancakes made in a certain month: the thickness in mm (millimetres) and the diameter in cm (centimetres). Each record on the file contains the two measurements for a pancake, thickness followed by diameter. The last record in the file contains values of 99 for each measurement. Design a program that will read the Pancake file, calculate the minimum, the maximum and the average for both dimensions, and print these values on a report.

Answer 1

#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;

int main() {
    int n;
    int min_th, max_th, thickness, sum_th;
    int min_d, max_d, diameter, sum_d;
    ifstream ifs("pancake.txt");

    n = 0;
    min_th = min_d = 999;
    max_th = max_d = 0;
    sum_th = sum_d = 0;
    while (ifs) {
        ifs >> thickness >> diameter;
        if (thickness == 99 && diameter == 99) {
            break;
        }

        sum_th += thickness;
        if (min_th > thickness) {
            min_th = thickness;
        }
        if (max_th < thickness) {
            max_th = thickness;
        }

        sum_d += diameter;
        if (min_d > diameter) {
            min_d = diameter;
        }
        if (max_d < diameter) {
            max_d = diameter;
        }

        n++;
    }

    double avg_th, avg_d;
    avg_th = static_cast<double>(sum_th) / n;
    avg_d = static_cast<double>(sum_d) / n;

    cout << "Thickness (mm): min = " << min_th << ", max = " << max_th
         << fixed << setprecision(2) << ", average = " << avg_th << endl;
    cout << "Diameter (cm): min = " << min_d << ", max = " << max_d
         << fixed << setprecision(2) << ", average = " << avg_d << endl;

    return 0;
}