Answer to Question #310898 in C++ for Secret Agent

Question

As I've said before, there are three types of numbers: the positive, the zero, and the negative ones. Today, we shall pay attention only to the negative ones now. Make a loop that will accept random decimal/float numbers. When the user inputs 0, the loop will terminate and then output the sum of all negative numbers inputted in 3 decimal places.

Let's code this.

Input

Multiple lines containing a decimal.

2.4434
-1.3433
-2.444
6.432
0

Output

A line containing a decimal with three decimal places.

-3.787

Answer 1

Here is program:

int main()
{


	const int size = 6;
	double dec[size]{};
	double total;
	for (int i = 0; i < size; i++)
	{
		cin >> dec[i];
		total += dec[i];
	}
	total = total / size;
	cout << total << endl;
}