Answer to Question #306541 in C++ for sanza

Question

Write a program that computes the cost of a long distance call. The cost of the call is determined according to .

• A call made between 8 AM and 6 PM is at a rate of 6 rupees per minute.

• A call made before 8 AM or after 6 PM is charged at a rate of 3.75 rupees.

if call starts at any time between 8:00 AM and 6:00 PM, and it ends after 6:00 PM then it will be charged at the rate of 6 rupees per min for the time before 6:00 PM and for rest of time the rate will be 3.75 rupees per min For example if call starts at 5:55 PM and ends at 6:05 PM then charges on this call be 48.75(30 rupees for first 5 mins and 18.75 rupees for rest of the time) if a call starts at time before 8:00 AM but ends after 8:00 AM then it will charged at rate of 3.75 rupees for time before 8:00 AM and for remaining minutes after 8:00 AM the rate will 6 rupees per min. For example if a call starts at 7:49 AM and ends at 8:01 AM the charge on that call will be 47.25 rupees (41.25 for first 11 min and 6 rupees for last min).

Answer 1

#include  <iostream>
#include <iomanip>
#include <sstream>
#include <string>
using namespace std;

int time2min(string& str) {
    istringstream istr(str);
    int h, m;
    string ampm;
    char ch;
    int res;

    istr >> h >> ch >> m >> ampm;
    res = h*60;
    res += m;
    if (ampm == "PM") {
        res += 12*60;
    }
    return res;
}


int main() {
    string str;
    int t1=time2min(string("8:00 AM"));
    int t2=time2min(string("6:00 PM"));
    int start, end;

    cout << "Enter start time: ";
    getline(cin, str);
    start = time2min(str);
    cout << "Enter end time: ";
    getline(cin, str);
    end = time2min(str);

    double cost = 0.0;
    if (end <= t1 || start >= t2) {
        cost = (end - start) * 3.75;
    }
    else if (t1 <= start && end <= t2) {
        cost = (end - start) * 6;
    }
    else if (start <= t1) {
        cost = (t1 - start) * 3.75;
        cost += (end - t1) * 6;
    }
    else {
        cost = (t2 - start) * 6;
        cost += (end - t2) * 3.75;
    }

    cout << "The cost is " << fixed << setprecision(2) << cost;

    return 0;
}