Answer to Question #305896 in C++ for Magisk

Question

Instructions:

1. You are provided with the isLeapYear() function which is already declared and defined for you.

2. Your task is to ask the user for a year and then call the isLeapYear function to check whether the year is a leap year or not.

Input

1. Year to be checked

Output

If a certain year is a leap year, print "<INSERT_YEAR_HERE> is a leap year"

Otherwise, print "<INSERT_YEAR_HERE> is not a leap year"

Sample Output:

Enter·year:·2020

2020·is·a·leap·year

This is the given code:

#include <iostream>

using namespace std;

int isLeapYear(int);

int main(void) {

// TODO: Write your code here

return 0;

}

int isLeapYear(int n) {

if(

(n % 4 == 0 && n % 100 != 0) ||

(n % 100 == 0 && n % 400 == 0)

) {

return 1;

}

return 0;

}

Answer 1

#include <iostream>
using namespace std;


int isLeapYear(int);


int isLeapYear(int n) 
{
	if((n % 4 == 0 && n % 100 != 0) || (n % 100 == 0 && n % 400 == 0)) 
	{
		return 1;
	}
	return 0;
}


int main(void) 
{
	// TODO: Write your code here
	int Yr,Flag=1;
	
	while(Flag)
	{
		cout<<"\n\tEnter a Year: "; cin>>Yr;
		if(isLeapYear(Yr)) 	cout<<"\n\t"<<Yr<<" is a leap year.";
		else				cout<<"\n\t"<<Yr<<" is not a leap year.";
		cout<<"\n\tPress 1 to continue or 0 to QUIT: "; cin>>Flag;		
	}
	return 0;
}