Answer to Question #300359 in C++ for Adi

Question

Write a program that takes a 2D pointer array and calculate sum of even and odd using recursive

function.

int sum(int **array, int row, int column, int &evenSum, int &oddSum)

Answer 1

#include <iostream>

using namespace std;

int sum(int **array, int row, int column, int &evenSum, int &oddSum)
{
	static int cl = column;
	if (array[row][column] % 2 == 0)
	{
		evenSum += array[row][column];
	}
	else
	{
		oddSum+= array[row][column];
	}
	if (column > 0)
		return sum(array, row, column-1, evenSum, oddSum);
	else if (row > 0)
	{
		row--;
		column = cl;
		return sum(array, row, column, evenSum, oddSum);
	}
	else return 0;
}


int main()
{
	int row,col;
	cout << "Please, enter a number of rows: ";
	cin >> row;
	cout << "Please, enter a number of cols: ";
	cin >> col;
	int **arr = new int*[row];
	for (int i = 0; i < row; i++)
	{
		arr[i] = new int[col];
	}

	for (int i = 0; i < row; i++)
	{
		for (int j = 0; j < col; j++)
		{
			cout << "Please, enter a value of arr[" << i << "][" << j << "]: ";
			cin>>arr[i][j];
		}
	}
	for (int i = 0; i < row; i++)
	{
		for (int j = 0; j < col; j++)
		{
			cout<< arr[i][j]<<" ";
		}
		cout << endl;
	}
	int oddSum=0;
	int evenSum=0;
	sum(arr,row-1, col-1, evenSum, oddSum);
	cout << "OddSum is " << oddSum;
	cout << "\nEvenSum is " << evenSum;
}