Answer to Question #291307 in C++ for ali

Question

 Create a program that loops 30 times, but only outputs numbers that are not divisible by 3 or 5. Decide on the most appropriate form of a loop, and use an if statement inside it

Answer 1

#include <iostream>


using namespace std;


int main(){
		
	for(int i=0;i<=30;i++){
		if(i%3!=0 && i%5!=0){
			cout<<i<<"\n";	
		}
	}
	system("pause");
	return 0;
}