Answer to Question #283749 in C++ for Collay

Question

3. There was a Three

by CodeChum Admin

I'm bored with just basic counting. How about we do some complex things this time? But I don't want to be associated with any number that's not divisible by 3.

Think you can handle this?

Instructions:

Print out all numbers from 1 to 100 that is divisible by 3, each in separate lines, using a for loop.

Output

Multiple lines containing an integer that is divisible by 3.

3

6

9

12

15

18

21

24

27

30

33

36

39

42

45

48

51

54

57

60

63

66

69

72

75

78

81

84

87

90

93

96

99

Answer 1

#include <iostream>


using namespace std;


int main()
{
    for (int i = 1; i < 101; i++) {
        if (i%3==0) cout << i << '\n';
    }


    return 0;
}