Answer to Question #282011 in C++ for devi

Question

Given a sorted array of distinct integers and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You must write an algorithm with O(log n) runtime complexity.

Answer 1

#include <iostream>


int index(int* arr, const int size, int value)
{
    for (int i = 0; i != size; ++i)
    {
        if (arr[i] == value)
        {
            return i;
        }
        else if (arr[i] < value && value < arr[i + 1])
        {
            return i + 1;
        }
    }
}


int main()
{
    int arr[5] = { 1, 3, 5, 9, 11 };
    std::cout << index(arr, 5, 4);
    


    return 0;
}