Answer to Question #277571 in C++ for Ana

Question

Write a program that prompts users to pick either a seat or a price. Mark sold seats by changing the

price to -1. When a user specifies a seat (11 = first row first col (shown in bold on seating plan)), make

sure it is valid and available. When a user specifies a price, find any seat with that price. User should

enter -99 to exit.

Answer 1

#include <iostream>
#include <string>
using namespace std;








int main() {
	int  seatPrices[10][10]={ 
		{ 10, 10, 10, 10, 10, 10, 10, 10, 10, 10 },
		{ 10, 10, 10, 10, 10, 10, 10, 10, 10, 10 }, 
		{ 10, 10, 10, 10, 10, 10, 10, 10, 10, 10 }, 
		{ 10, 10, 20, 20, 20, 20, 20, 20, 10, 10 }, 
		{ 10, 10, 20, 20, 20, 20, 20, 20, 10, 10 }, 
		{ 10, 10, 20, 20, 20, 20, 20, 20, 10, 10 },
		{ 20, 20, 30, 30, 40, 40, 30, 30, 20, 20 },
		{ 20, 30, 30, 40, 50, 50, 40, 30, 30, 20 },
		{ 30, 40, 50, 50, 50, 50, 50, 50, 40, 30 },
	};
	int ch=-1;
	int seatRow;
	int seatCol;
	int price;
	do{
		cout<<"Pick by Seat <1> or Price <2> or Quit <-99>: ";
		cin>>ch;


		if(ch==1){
			do{
				cout<<"Enter row seat [1-10]: ";
				cin>>seatRow;
			}while(seatRow<1 || seatRow>10);
			do{
				cout<<"Enter column seat [1-10]: ";
				cin>>seatCol;
			}while(seatCol<1 || seatCol>10);
			if(seatPrices[seatRow-1][seatCol-1]!=-1){
				cout<<"The seat price is: "<<seatPrices[seatRow-1][seatCol-1]<<"\n\n";
				seatPrices[seatRow-1][seatCol-1]=-1;
			}else{
				cout<<"The seat is sold\n\n";
			}
			
			
		}else if(ch==2){
			do{
				cout<<"Enter seat price [10-50]: ";
				cin>>price;
			}while(price<10 || price>50);


			for(int i=0;i<10;i++){
				for(int j=0;j<10;j++){
					if(price==seatPrices[i][j] && seatPrices[i][j]!=-1){
						cout<<"The seat with that price is: row: "<<(i+1)<<", column: "<<(j+1)<<"\n";	
						seatPrices[i][j]=-1;
						i=100;
						j=100;
					}
				}
			}
			cout<<"\n\n";


		}else if(ch==-99){
			//exit
		}
	}while(ch!=-99);






	return 0;
}