Answer to Question #271459 in C++ for Nokachi

Question

Remember the game of FizzBuzz from the last time? Well, I thought of some changes in the game, and also with the help of loops as well. Firstly, you'll be asking for a random integer and then loop from 1 until that integer. Then, implement these conditions in the game:

• print "Fizz" if the number is divisible by 3
• print "Buzz" if the number is divisible by 5
• print "FizzBuzz" if the number is divisible by both 3 and 5
• print the number itself if none of the above conditions are met

Answer 1

#include <iostream>
using namespace std;
void fizzBuzz(int n){
    if(!(n%3)){
        cout<<"Fizz";
    }
    if(!(n%5)){
        cout<<"Buzz";
    }
    else if(n%3 && n%5){
        cout<<n;
    }
    cout<<endl;
}
int main(){
    int n;
    cout<<"Input the integer: ";
    cin>>n;
    for(int i = 1; i <= n; i++){
        fizzBuzz(i);
    }
    return 0;
}