Answer to Question #269877 in C++ for oman

Question

1. Calculate the value of a function y=2x^2+15 with x varying from 1 to 20 in increments of 0.5.

Answer 1

#include<iostream>
#include<math.h>
using namespace std;
int main()
{
	 double x;
	 double y;
	 for(x=1;x<=20;x+=0.5){
	 y=2*pow(x,2)+15;
	 cout<<"Value is: "<<y<<endl;
	 
}}