Answer to Question #269162 in C++ for kool

Question

Define a class ABC. Derive two classes BBC and KBC from ABC. All the classes contains same member function name as display(). The base class pointer always holds the derived class objects.

Answer 1

#include <iostream>
using namespace std;

class ABC 
{
public:
    ABC(int id=0) : id(id) {}
    void display() {
        cout << "ABC: " << id << endl;
    }
protected:
    int id;
};

class BBC : public ABC 
{
public:
    BBC(int id=0) : ABC(id) {}
    void display() {
        cout << "BBC: " << id << endl;
    }   
};

class KBC : private ABC
{
public:
    KBC(int id=0) : ABC(id) {}
    void display() {
        cout << "KBC: " << id << endl;
    }   
};

int main()
{
    ABC *p = new ABC(1);

    cout << "Pointer to ABC:" << endl << endl;
    p->display();
    delete p;

    p = new BBC(2);
    cout << "Pointer to BBC:" << endl << endl;
    p->display();
    delete p;

    p = reinterpret_cast<ABC*>(new KBC(3));
    cout << "Pointer to KBC:" << endl << endl;
    p->display();
    delete p;

}