Answer to Question #268663 in C++ for zain

Question

ABS assignment

your mother asked you to stack up all your books in a book rack. A book rack can not hold more than 25 books. so create an ADT called book that stores the name, author, and the number of pages in a book. use this ADT to create an array based stack called "bookrack" of books. your implementation must be abstraction based containing:

1. Accessors

2. Mutators,

3. push

4. pop

5. peek

6. smart_search

7. display stack

8. isEmpty

9. isFull

10. delete

remember that you are implementing a stack which is a variation of a linked list in which operations can be performed only at the head. So for operations such as search, display and delete, you will have to be very careful about 1. conform to the rules of the stack i.e work with the top item only, 2. maintain the order of the stack.

Answer 1

#include<stdio.h>
#include<iostream>
using namespace std;


class Stack
{
int top;
int arr[25];
string name;
int num;
string author;


public:
    Stack()
{
       top=-1;
}


    void push();
    void smart_search();
    //int delete();
    void pop();
    void view();
    int isEmpty();
    int isFull();
};


int Stack::isEmpty()
{
    return (top==(-1)?1:0);
}


int Stack::isFull()
{
    return ( top == 50 ? 1 : 0 );
}
void Stack::smart_search(){
	
}


void Stack::push()
{
    if(isFull())
    {
        cout<<"\nSTACK IS FULL OVERFLOW ";
    }
    else
    {
        int x;
        cout<<"\nEnter an element :: ";
        cin>>x;
        ++top;
        arr[top]=x;
        cout<<"\nInsertion successful.\n";
    }
}


void Stack::pop()
{
    int num;
    if(isEmpty())
    {
            cout<<"\n STACK IS EMPTY [ UNDERFLOW ] ";
    }
    else
    {
    cout<<"\nDeleted item is : "<<arr[top]<<"\n";
    top--;
    }
}


void Stack::view()
{
    if(isEmpty())
    {
            cout<<"\n STACK IS EMPTY [ UNDERFLOW ] ";
    }
    else
    {
    cout<<"\nSTACK :\n";
    for(int i=top;i>=0;i--)
    {
            cout<<arr[i]<<"\n";
    }
    }
}




int main()
{
    Stack s;
    int option;
    option=0;
    


    while(option!=4)
    {
        cout<<"\n1. Push\n";
        cout<<"2. Pop\n";
        cout<<"3. Display\n";
        cout<<"4. Quit\n";
        cout<<"\nEnter your Choice :: ";
        cin>>option;


        if(option==1){
                s.push();}


        else if(option==2){
                s.pop();
                }


        else if(option==3){
                s.view();
              }


        else if(option==4){
                cout<<"\nPress any key .. ";
               }


        else{
                cout<<"\nWrong Choice!! \n";
                }
        }


    return 0;
}