Answer to Question #268200 in C++ for Amit

Question

Write a program such that base class pointer or reference will always access/call the base version of the members available in derived class, do not have any access to the derived class members.

Answer 1

#include <iostream>
using namespace std;
class base {
public:
	virtual void print()
	{
		cout << "print base class" << endl;
	}
	void show()
	{
		cout << "show base class" << endl;
	}
};

class derived : public base {
public:
	void print()
	{
		cout << "print derived class" << endl;
	}
	void show()
	{
		cout << "show derived class" << endl;
	}
};
int main()
{
	base* bptr;
	derived d;
	bptr = &d;
	bptr->print();
	bptr->show();
}