Answer to Question #264636 in C++ for DANISH

Question

why this switch statment is not valid??? reason

switch (n % 10)

case 2:

{

case 4:

case 6:

case 8:

cout << "Even";

break; case 1:

case 3:

case 5:

case 7:

cout << "Odd"; break; }

Answer 1

The first reason in the function int main n was not declared.

The second reason the syntax for the switch case is wrong. The correct syntax for switch case is

switch(expression) {
   case constant-expression  :
      statement(s);
      break; //optional
   case constant-expression  :
      statement(s);
      break; //optional
  
   // you can have any number of case statements.
   default : //Optional
      statement(s);
}

A switch statement is subject to the following rules.

In a switch statement, the expression must be of an integral or enumerated type, or of a class type with a single conversion function to an integral or enumerated type.

A switch can contain any number of case statements. Each case is followed by a colon and the value to be compared to.

A case's constant expression must be of the same data type as the switch's variable, and it must be either a constant or a literal.

When the variable being turned on equals a case, the statements that follow it will run until a break statement is reached.

The switch terminates when a break statement is reached, and the flow of control jumps to the line after the switch statement.

A break isn't required in every circumstance. If no break exists, the control flow will continue through the following cases until a break is found.

A default case can be specified in a switch statement and must occur at the end of the switch. When none of the other situations are true, the default case can be utilized to complete a task. In the default instance, no break is required.