Answer to Question #262662 in C++ for Mowgli10

Question

Given a string, an integer position, and an integer length, all on separate lines, replace choiceLen number of characters with "(removed)" starting at that position in the string. Then, output the result.

Ex: If the input is:

Fuzzy bear

3

4

the output is:

Fuz(removed)ear

Answer 1

SOLUTION TO THE ABOVE QUESTION

SOLUTION CODE

#include<iostream>
#include <string>
using namespace std;
int main()
{
    string my_string;
    cout<<"Enter your string: ";
    getline(cin, my_string);
    int integer_position;
    cout<<"Enter an integer position: ";
    cin>>integer_position;
    int integer_length;
    cout<<"Enter an integer length: ";
    
    cin>>integer_length;
    
    //print your original string
    cout<<"\nMy original string is: "<<my_string<<endl;
    
    int my_string_length = my_string.length();
    //declare a new string to append toit
    string my_new_string = "";
    
    int counter = 0;
    while(counter<my_string_length)
    {
    
		if(counter==integer_position)
		{
			string string_to_add = "(removed)";
			my_new_string+=string_to_add;
		}
		else if(counter>integer_position && counter<(integer_length+integer_position))
		{
			//do nothing
		}
		else
		{
    	    //if character not to be removed
            // string(1,x) converts character 'x' to string "x"
            my_new_string+=string(1,my_string[counter]); //apend to new str
		
		}
		
		counter = counter + 1;
	}
    //print your new string
    cout<<"\nMy new string is: "<<my_new_string<<endl;
    
    return 0;
}

SAMPLE OUTPUT PROGRAM