Answer to Question #256704 in C++ for Dion Martins

Question #256704

Write an algorithm that will accept the following for 100 students: The students’ name (studName) and 3 test marks (marks), as well as one exam mark (examMark). The program must calculate the final mark (finMark) for every student. The final mark comprises of 50% of the exam mark added to 50% of the average (agv) of the 3 tests. Display the final mark for every student.


1.Mix the for loop with a do-while


1
Expert's answer
2021-11-03T07:44:25-0400
#include <iostream>
#include <string>
#include <vector>
 
using namespace std;
 
class Student
{
public:
	Student(string name, int exam, int mark1, int mark2, int mark3);
	void Display();
private:
	string nameS;
	int examS;
	int mark1S;
	int mark2S;
	int mark3S;
	int finalMark;
};
 
Student::Student(string name, int exam, int mark1, int mark2, int mark3) : nameS(name), examS(exam), mark1S(mark1), mark2S(mark2), mark3S(mark3)
{
	finalMark = (examS + (mark1S + mark2S + mark3S) / 3) / 2;
}
 
void Student::Display()
{
	cout << nameS << ": " << finalMark << endl;
}
 
int main()
{
	vector<Student> CLASS;
	string name;
	int exam, mark1, mark2, mark3;
	// until quantity of students is 100 or we enter Student name 000
	do
	{
		cout << "Enter student name (enter name 000 to exit): ";
		cin >> name;
		if (name == "000")
		{
			cout << "All student were entered!" << endl << endl;
			break;
		}
		cout << "Enter exam: ";
		cin >> exam;
		cout << "Enter 3 mark using space: ";
		cin >> mark1 >> mark2 >> mark3;
		CLASS.push_back(Student(name, exam, mark1, mark2, mark3));		// put Student in class
 
	} while (CLASS.size() < 101);										// quantity student less than 101
 
	// Display student that we have entered
	cout << "Students in class!!" << endl;
	int i = 0;
	while (i < CLASS.size())
	{
		CLASS[i++].Display();
	}
	cout << "End of program" << endl;
	system("pause");
	return 0;
}

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