Answer to Question #237755 in C++ for HIMANSHU

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Question #237755

Show that n = O(nlogn).

Expert's answer

You can prove it by applying L'Hospitals rule to lim n-> infinity of n/nlogn

g(n) =n and f(n)=nlogn

Derivate g(n) and f(n) so you will get:

1/(n)

1/infinity =0 so n=O(nlogn) is true.

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