Answer to Question #231684 in C++ for Yasas Sri Silva

Question

The function takes a 4-digit integer as parameter, validates the integer and returns 1 when the digits are in increasing order or 2 when the digits are in decreasing order or 0 when the digits are not in any order.

Answer 1

#include <iostream>




using namespace std;




int checkInteger(int num){
	int number=num;
	int currentDigit = number % 10;
	number = number/10;
	int counter=0;
	int numberOfDigits=0;
	while(number>0){
		if(currentDigit > number % 10){
			counter++;
		}
		currentDigit = number % 10;
		number = number/10;
		numberOfDigits++;
	}
	if(counter==numberOfDigits){
		return 1;
	}else{
		number=num;
		currentDigit = number % 10;
		number = number/10;
		counter=0;
		numberOfDigits=0;
		while(number>0){
			if(currentDigit < number % 10){
				counter++;
			}
			currentDigit = number % 10;
			number = number/10;
			numberOfDigits++;
		}
		if(counter==numberOfDigits){
			return 2;
		}
	}


	return 0;
} 




int main(){


	int number=4321;
	cout << "Enter 4-digit integer: ";
	cin>>number;
	if(checkInteger(number)==1){
		cout<<"The digits are in increasing order.\n";
	}else if(checkInteger(number)==2){
		cout<<"The digits are in decreasing order.\n";
	}else{
		cout<<"The digits are not in any order.\n";
	}




	system("pause");
	return 0;
}