Answer to Question #220295 in C++ for wawiee

Question

You are requested by a SuperStore (Spar) in Soshanguve to calculate it’s earning for the week (the

store opens the entire week) and determine the day with the highest and lowest earnings. The

Store comprises of two sections namely the Food section and the Liquor store.

Your C++ program should prompt the total sales for each section for each day and store the

total sales for the day into an array. At the end of the week It should display a report for

Management for the total sales for that week, the day the lowest sales and the day with the

highest sales were recorded.

Answer 1

#include<iostream>
using namespace std;
double getMin(double arr[], int n)
{
    
    return (n == 1) ? arr[0] : min(arr[0],
                         getMin(arr + 1, n - 1));
}
int main(){
    string week[7] = {"Sunday", "Monday", "Tuesday", "Wednesday","Thursday", "Friday","Saturday"};
    double sales [7];
    for(int i =0; i<7; i++){
        cout<<"Enter the sales for day "<<(i + 1)<<endl;
        cin>>sales[i];
    }
    double max = sales[0];
    for(int i=0; i<7; i++){
        if(sales[i] > max){
            max = sales[i];
        }
    }
    double total = 0;
    int indexH =0;
    int indexL = 0;
   for(int i =0; i<7; i++){
       total += sales[i];
       if(sales[i] == max){
           indexH = i;
       }
       else if(sales[i] == getMin(sales, 7)){
           indexL = i;
       }
       
   }
   cout<<"The total sales is \t"<<total<<endl;
    cout<<"The day with highest sales \t"<<week[indexH]<<"\nThe day with lowest sales\t"<< week[indexL];
    
}