Answer to Question #213955 in C++ for ali

Question

Write output of given code segments and explain it logically, answer without explanation will be awarded zero marks. 

#include<iostream>

using namespace std;

 

class Base

{

public:

    virtual void show() { cout<<" In Base \n"; }

};

 

class Derived: public Base

{

public:

    void show() { cout<<"In Derived \n"; }

};

 

int main(void)

{

    Base *bp, b;

    Derived d;

    bp = &d;

    bp->show();

    bp = &b;

    bp->show();

    return 0;

}

Answer 1

output

In Derived

In Base

explanation

 Initially base pointer points to a derived class object. Later it points to base class object