Question

Program to find the sum of the series 1+2+3...+n
Program to find the sum of the series 1(pow)+2(pow)+3(pow)...+n(pow)

Answer 1

#include <iostream>
#include <conio.h>
#include <math.h>

using namespace std;

long sum_1(int n)
{
return n * (1 + n) / 2;
}

long sum_2(int n, int m)
{
long result = 0;
for (n; n > 0; n--)
result += (long)pow((long double)n, m);
return result;
}

void main()
{
int n, m;
cout << "Enter n: ";
cin >> n;
cout << "Enter m: ";
cin >> m;

cout << "The sum of the 1st series is: " << sum_1(n) << endl;
cout << "The sum of the 2nd series is: " << sum_2(n, m) << endl;
getch();
}