Answer to Question #200651 in C++ for ifhaam iftikhar

Question

1. Program the following. Implement the following equation 3x4 sin(180x) + 4x3 cos(90x) + x2 sin(tan(45)) + 7x + 9cos(90x2 ) where x may be user defined value. 2. Program the following.  Prompt user to input distance in Kilometers and display it in meters.  Input any number from user and generate its square e.g. square of 8 is 64  Input any number from user and generate its cube e.g. cube of 8 is 512  Input a 4 digit number in any integer type variable and sum all the four digits, e.g. int a =3487, result = 22  Generate the table for a number input by the user.  For the following equation 3x4 + 4x3 + x2 + 7x + 9, substitute the user provided value of x and generate the result.

Answer 1

#include<iostream>
#include<bits/stdc++.h>
using namespace std;

int main()
{
	cout<<"Enter the value of x : ";
	int x;
	cin>>x;
	int eq = (3*(pow(x,4)*sin(180*x))) + (4*pow(x,3)*cos(0*x)) + (pow(x,2)*sin(tan(45)))+ (7*x) + (9*cos(90*(pow(x,2))));
	cout<<"Value of eqn (3*(pow(x,4)*sin(180*x))) + (4*pow(x,3)*cos(0*x)) + (pow(x,2)*sin(tan(45)))+ (7*x) + (9*cos(90*(pow(x,2)))) is : "<<eq<<endl;
	cout<<endl;
	cout<<"Enter distance in kilometers : ";
	int km;
	cin>>km;
	cout<<"Distance in meters : "<<km*1000<<endl<<endl;
	cout<<"Enter a number : ";
	int n;
	cin>>n;
	cout<<"Square of "<<n<<" : "<<pow(n,2)<<endl<<endl;
	cout<<"Enter a 4-digit number : ";
	int num;
	cin>>num;
	int sum=0;
	while(num>0)
	{
		int rem = num%10;
		sum += rem;
		num = num/10;
	}
	cout<<"Sum of digits : "<<sum<<endl<<endl;
	cout<<"Enter a number for which u want to see its table : ";
	int t;
	cin>>t;
	cout<<"Table of t"<<endl<<"--------------------"<<endl<<endl;
	for(int i=1; i<=10; i++)
	{
		cout<<t<<" * "<<i<<" = "<<t*i<<endl;
	}
	
	int m;
	cout<<endl;
	cout<<"Enter a number : ";
	cin>>m;
	int ans = (3*pow(m,2)) + (4*pow(m,3)) + pow(m,2) + (7*m) + 9;
	cout<<"Value of eqn (3*pow(m,2)) + (4*pow(m,3)) + pow(m,2) + (7*m) + 9 is ";
	cout<<ans<<endl;
}