Answer to Question #198416 in C++ for M Kamran

Question

Write a function to find binary equivalent of given decimal number.

 

Important note:

You have to display a switch menu like this:

 

Press <1> for Problem 1

Press <2> for Problem 2

Press <3> for Problem 3

Press <4> for Problem 4

Press <0> for exit

 

When user presses 1 your program should execute problem 1, when he/she press 2 it should execute problem 2 and so on. It clearly shows that you have to do the whole lab in one .c file.

Answer 1

To find the binary equivalent of the given number run the program and input 1. Other cases (2,3,4) doesn't work because you didn't provide Problem 2, Problem 3 and Problem 4. To quit the program input 0.

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>


int read_int() {
    int number;
    scanf("%d", &number);
    return number;
}


// function to find the binary representation of a decimal number
void bin(int n)
{
    int b[32];
    int i = 0;
    while (n > 0) {
        b[i] = n % 2;
        n = n / 2;
        i++;
    }
    for (int j = i - 1; j >= 0; j--)
        printf("%d", b[j]);
}


int main()
{
   printf("Press <1> for Problem 1\nPress <2> for Problem 2\nPress <3> for Problem 3\nPress <4> for Problem 4\nPress <0> for exit\n");
    int n = read_int(), num;
    switch(n) {
        case 1:
            printf("Input a decimal number: ");
            num = read_int();
            printf("Binary representation of %d is ", num);
            bin(num);
            printf("\n");
            break;
        case 2:
            printf("The Problem 2 doesn't exist\n");
            printf("\n");
            break;
        case 3:
            printf("The Problem 2 doesn't exist\n");
            printf("\n");
            break;
        case 4:
            printf("The Problem 2 doesn't exist\n");
            printf("\n");
            break;
        case 0:
            return 1;
        default:
            printf("Input a number between [1:4] or input 0 to quit: ");
            printf("\n");
    }


    return 0;
}