Answer-:
- Suppose taking university registration number is -:181500333; so, taking last three digit is 333.
- (333)10 => ( )2
we convert it decimal to binary
so, (333)10 => ( 101001101)2
Question 3 :- Add 1 in part b
101001101 +1⟹ 101001110
so, the answer is (101001110)2
Question 4 :- answer of question 3 is converted into hexadecimal
(101001110)2 => ()16
divided in 3 part 4 bits each
=>
0001 0100 1110 1 4 E
so (101001110)2 => (14E)16
question 5 :- taking answer of part c
(101001110)2 => ( )10
=> (334)10 Ans.
question 6 :- Consider a hexadecimal no . is (AAA)16 so it convert into binary number
=>
A A A 1010 1010 1010
so, answer is (AAA)16 => (101010101010)2
Question 7, :- Given Binary is (1100111110100000)2 => ( )16
=>
1100 1111 1010 0000 C F A 0
so, Answer is (CFA0)16.
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