Answer to Question #189670 in C++ for Sydney Nthane

Question

A bookshop gives discount to customers as follows:  Students get 10% discount,  Book dealers get 12% discount and  Pensioners get 15% discount.  All other customers get 10% discount only if their total purchases are more than R200. You are requested to write two versions of a program that calculates and displays the final amount that is due, after discount. (i) The first version of the program uses a switch statement to implement the above program. (ii) The second version of the program uses nested-if statements. Hint: Use the following variables: float amount; // the amount due before discount char customerType; // the type of customer: 'S' (student) or // 'D' (dealer) or 'P' (pensioner) or // 'O'(other) float discount, finalAmount; 

Answer 1

#include <iostream>
using namespace std;
int main()
{
	// Part I
	double sum;
	char ch;
	cout << "Enter type of discount (S, D, P, O): ";
	cin >> ch;
	cout << "Enter sum of purchases: ";
	cin >> sum;
	switch (ch)
	{
	case 'S':
	{
		cout << "Sum with discount is: R" << sum * 0.9 << endl;
		break;
	}
	case 'D':
	{
		cout << "Sum with discount is: R" << sum * 0.88 << endl;
		break;
	}
	case 'P':
	{
		cout << "Sum with discount is: R" << sum * 0.85 << endl;
		break;
	}
	case 'O':
	{
		if (sum > 200) cout << "Sum with discount is: R" << sum * 0.9 << endl;
		else cout << "Sum with discount is: R" << sum << endl;
		break;
	}
	default:
		cout << "Wrong value!" << endl;
		break;
	}
	cout << endl;
	cout << "Enter type of discount (S, D, P, O): ";
	cin >> ch;
	cout << "Enter sum of purchases: ";
	cin >> sum;
	if (ch == 'S') cout << "Sum with discount is: R" << sum * 0.9 << endl;
	else if (ch == 'D') cout << "Sum with discount is: R" << sum * 0.88 << endl;
	else if (ch == 'P') cout << "Sum with discount is: R" << sum * 0.85 << endl;
	else if (ch == 'O')
	{
		if (sum > 200) cout << "Sum with discount is: R" << sum * 0.9 << endl;
		else cout << "Sum with discount is: R" << sum << endl;
	}
	else cout << "Wrong value!" << endl;
	return 0;
}