Answer to Question #189342 in C++ for Dunga

Question

1. Create a class named Time that contains integer fields for hours and minutes. Store the hour in military time that is, 0 to 23. Add a function that displays the fields, using a colon to separate hours and minutes. (Make sure the minutes displays as two digits. For example, 3 o’clock should display at 3:00, not 3:0). Add another function that takes an argument that represents minutes to add to the time. The function updates the time based on the number of minutes added. For example, 12:30 plus 15 is 12:45, 14:50 plus 20 is 15:10, and 23:59 plus 2 is 0:01. The Time constructor ensures that the hour field is not greater than 23 and that the minutes field is not greater than 59; default to these maximum values if the arguments to the constructor are out of range. Create a main() function that instantiates an array of at least four Time objects and demonstrates that they display correctly both before and after varying amounts of time have been added to them.

Answer 1

Answer:-

#include <iostream>
using namespace std;
class Time{
    int hours, minutes;
    public:
    Time(){}
    Time(int hrs, int min){
        hours = hrs;
        minutes = min;
        if(hours > 23) hours = 23;
        if(minutes > 59) minutes = 59;
    }
    void show(){
        cout<<this->hours<<":";
        if(this->minutes < 10) cout<<0;
        cout<<this->minutes<<endl;
    }
    Time add(int m){
        this->minutes += m;
        while(minutes >= 60){
            this->minutes -= 60;
            this->hours++;
        }
        while(this->hours > 23) this->hours -= 24;
        return *this;
    }
};
int main(){
    Time times[4] = {Time(23, 59), Time(24, 67), Time(0, 0), Time(3, 0)};
    for(int i = 0; i < 4; i++) times[i].show();
    cout<<endl;
    times[0].add(2).show();
    times[1].add(1).show();
    times[2].add(60).show();
    times[3].add(2881).show(); 
    return 0;
}