Answer to Question #188444 in C++ for Shaikh Shahid Raaz

Question

Write a program which has a class named binary which has a character array to store a binary string. The class decimal derives from class binary and contains an integer data member. Another class called octal also derives from binary. Each class should contain constructors and appropriate data members to input and display the elements. The display function of binary class displays the binary equivalent, octal class’s display function displays octal equivalent whereas decimal class’s display function displays the decimal equivalent

please dont use bitset stream ,use user define method for conversion

Answer 1

#include<bits/stdc++.h>
#include<iostream>
using namespace std;
class binary
{
public:
    char s[30];
    binary()
    {
        cout<<"\nEnter a binary number ";
        cin>>s;
    }
    int isBinary(char s[])
    {
        int f=0;
        for(int i=0;i<strlen(s);i++)
            {
                if(s[i]!='0' && s[i]!='1')
                {
                    f=1;
                    break;
                }
            }
        if(f==0)
        {
            return 0;
        }
        else
        {
            return 1;
        }
    }
    void Display_binary()
    {
        if(isBinary(s)!=0)
        {
            cout<<"\nThis is not a binary number ";
        }
        else
        {
            cout<<"\nBinary Number is "<<s;
        }
    }
};
class decimal : public binary
{
 public:
     int a[30],i,sum=0;
     decimal()
     {
         for(int i=0;i<strlen(s);i++)
         {
             a[i]=s[i]-48;
         }
         for(int i=0;i<strlen(s);i++)
         {
             sum=pow(2,(strlen(s)-1-i))*a[i]+sum;
         }
     }
     void display()
     {
         cout<<"\nDecimal Number is "<<sum;
     }


};
class Octal : public binary
{
 public:
     int a[30],i,sum=0,f=1,oct;
     Octal()
     {
         for(int i=0;i<strlen(s);i++)
         {
             a[i]=s[i]-48;
         }
         for(int i=0;i<strlen(s);i++)
         {
             sum=pow(2,(strlen(s)-1-i))*a[i]+sum;
         }
         while (sum != 0)
         {
             oct += (sum % 8) * f;
             sum /= 8;
             f *= 10;
        }
     }
     void display()
     {
         cout<<"\nOctal Number is "<<oct;
     }


};
int main()
{
    decimal d1;
    d1.display();
    Octal o1;
    o1.display();
}