Answer to Question #173302 in C++ for Vigneshwaran. B

Question

Write a function Unique_Occurance and call the function to find the count of unique occurrence digits in a given number N. The number will be passed to the program as the input of type int.

Assumption: The input number will be a positive integer number>=1 and <= 25000.

For e.g.

If the given number is 292, the program should print 1 because there are only 1 unique occurrence digit "9" int this number.

Answer 1

#include <iostream>
using namespace std;
 
int UniqueDigits(int N);
 
int main()
{
   // Initialize a variable
   int N;
   cout << "Enter a positive integer number>=1 and <= 25000 : ";
   cin >> N;
   cout << endl;
   if(N >= 1 && N <= 25000)
        cout << UniqueDigits(N);  // Function Call
   return 0;
}
//**********************************************
// Function that returns the count of
// unique digits of the given number
int UniqueDigits(int N) 
{
   int res = 0;                 // count of unique digits
   int lastDigit = 0;       // last digit of N
   int i;
 
   // digitArray to store digit count
   int digitArray[10] = { 0 };
 
   // loop through the digits of N
   while (N > 0) {
            lastDigit = N % 10;            // Get the last digit N
            digitArray[lastDigit]++;   // counter of the last digit
            N = N / 10;                        // next last digit
   }
 
   // loop through the array digitArray 
   for ( i = 0; i < 10; i++) {
 
       // If frequency of digit is 1
       if (digitArray[i] == 1) {
            res++;            // count of unique digits
       }
   }
    return res;
}