Answer to Question #172499 in C++ for Raj

Question

Write a program to find the count of unique digits in a given number N. The number will be passed to the program as the input of type int.

Assumption: The input number will be a positive integer number>=1 and <= 25000.

For e.g.

If the given number is 292, the program should print 2 because there are only 2 unique digits "2" and "9" int this number.

Answer 1

#include <iostream>
#include <string>
using namespace std;
int main(){
    int b;
    bool flag = true;
    while(flag){
    cout<<"Input the number between 1 and 25000.\n";
    cin>>b;
    flag = true;
    if(b >= 1 && b <= 25000)
        flag = false;
    }
    string a = to_string(b);
    char unique[a.length()];
    int count = 0;


    for(int i = 0; i < a.length(); i++){
        flag = false;
        for(int j = 0; j < i; j++){
            if(a[i] == a[j]){
                flag = true;
                break;
            }
        }
        if(!flag){
            count++;
        }
    }
    cout<<count<<" unique digit(s) in "<<b;
    return 0;
}