Answer to Question #162927 in C++ for prajakta

Question

Write a program that takes as input two numbers n (integer) and x (double), and prints arctan(x) evaluated by taking n terms of the Taylor series (using x0 =0):

arctan(x) = x - x ³ /3 + x ⁵ /5 - x ⁷ /7 …

Answer 1

#include <iostream>
#include <cmath>
using namespace std;
int main () {
    int n, p = 1;
    double x, S = 0;
    cout << "n = "; cin >> n;
    cout << "x = "; cin >> x;
    for (int i = 1; i < n; i++) {
        if (i % 2 == 1) {
            S += p * pow(x, i) / i;
            p *= (-1);
        }
    }
    cout << "arctan(" << x << ") = " << S;
    return 0;
}