Answer to Question #156230 in C++ for Macky

Question

You need to create a program that uses loops to perform the following steps.

1. Allow the user to input two integers. Variables: Num1 and Num2 (Num1 must be less than Num2, values must be a positive number) (use loop); create a user-defined function to validate the user's input.

2. Output all even numbers between Num1 and Num2. (use loop); create a user-defined function. The function is a void function.

3. Output the sum of all odd numbers between Num1 and Num2. (use loop); create a user-defined function called sum(). Declare a variable called sumodd in the main() for the sum(). sum() is a value returning function. Use sumodd to hold a returned value.

Answer 1

#include<iostream>
using namespace std;
void even(int a,int b){
        cout<<"Even numbers"<<endl;
    while (a<=b){
        if(a%2==0){ cout<<a<<endl;   }
    ++a;
    
    }
}


int  odd(int a,int b){
    cout<<"Odd numbers"<<endl;
    int s=0;
    while (a<=b){
        if(a%2==1){ cout<<a<<endl;  
        
        s=s+a;
        }
    ++a;
    
    }
    return s;
}


void dation(){

    int num1,num2;
    bool d=false;
    while(d==false){
    cout<<"Enter First number"<<endl;
    cin>>num1;
    cout<<"Enter second number"<<endl;
    cin>>num2;
    if((num1<num2) && (num1>=0)){
    
    d=true;
    
    cout<<"first value="<<num1<<" second value="<<num2<<endl;    
    
    }else{
    
    
    cout<<"Entered wrong values:\n both values must be positive and first value must be less than second value\n try again"<<endl;
    
    }

    
    }


}


int main(){
    int a,b;
    cout<<" enter num1 and num2"<<endl;
    cin>>a>>b;

dation();
int sumodd=odd(a,b);
even(a,b);
cout<<"sum odd="<<sumodd<<endl;

return 0;}