Answer to Question #155732 in C++ for waleed

Question

Write a program that initialize array of size 10, and prints all Armstrong and Palindrome numbers in array. Your program should ask user about their choice of printing. If user press ‘A’ or ‘a’ then program should display all Armstrong numbers in array and if user press ‘P’ or ‘p’ then it should display all Palindrome numbers in array.

Answer 1

#include<iostream>
#include<math.h>
using namespace std;

int palindrome(int n){

int rv=0;
for(int i=n;i>0;i/=10)
rv=rv*10+i%10;
return(n==rv);

}

void armstrong(int num){

int dm[10],k=0;

    for(int j=1;j<=num;j++){
int original,rem,sum=0,n=0,dm[10],k=0;

original=num;
while(original!=0){

original/=10;
++n;
}
original=num;

while(original!=0){

rem=original%10;
sum+=pow(rem,n);
original/=10;
}

if((sum==num)&&(k<=10)){
cout<<num;
dm[k]=num;
k++;


}
    }


    for(int i=0;i<10;++i){
    cout<<dm[i]<<endl;
    
    }

}

void pal(int min,int max){
int dm[10],k=0;
for(int i=min;i<=max;i++)
if(palindrome(i)&& (k<=10)){
//cout<<i<<" ";
dm[k]=i;
k=k+1;
}
char c;
cout<<"Enter A or a for armstrong numbers or P o p for palidrone numbers"<<endl;
cin>>c;

for(i=0;i<10;i++){

if((c=='a') || (c=='A')){
armstrong(dm[i]);
}else

if((c=='P') || (c=='p')){
cout<<dm[i]<<endl;
}

}
}

int main(){
pal(100,200);
return 0;}