Answer to Question #149459 in C++ for Jochelle Buenaventura

Question

Create a program using a one-dimensional array that accepts five input values from the keyboard. Then it should also accept a number to search. This number is to be searched if it is among the five input values. If it is found, display the message “Searched number is found!”, otherwise display “Search number is lost!”.
Sample input/output dialogue:
Enter five numbers:
10 15 20 7 8
Enter a number to search: 7
Search number is found!

Answer 1

#include <iostream>

using namespace std;

int main()
{
    // we declare an one-dimensional array that accepts five element
    int arr[5];
    
    // we should enter the elements of array from keyboard
    cout << "Enter 5 numbers: " << endl;
    for (int i = 0; i < 5; i++) {
        cin >> arr[i];
    }
    cout << "The entered array is : " << endl;
    for (int i = 0; i < 5; i++) {
        cout << arr[i] << " ";
    }
    
    // we declare a variable for search the element in array
    int number_searched;
    cout << "\nEnter a number to search: " << endl;
    cin >> number_searched;
    int t = 0;
    for (int i = 0; i < 5; i++) {
        if (number_searched == arr[i]) {
            cout << "Searched number is found!";
            break;
        }
        t++;
    }
    if (t == 5) {
        cout << "Search number is lost!";
    }
    return 0;
}