Answer to Question #148466 in C++ for Sang Nguyen

Question

Solicit an integer number between 1 and 100 from the user. If the number is less than 50, calculate the average of the number and all positive values below it. If the number is 50 or higher, calculate the average of the number and all number between it and 100; and including 100

Answer 1

#include <iostream>
#include <iomanip>

using namespace std;

// calculating Average between N1 and N2 numbers
double Average(int N1, int N2)
{
    int Sum = 0;
    for (int i = N1; i <= N2; i++)
        Sum += i;
    return Sum / (static_cast<double>(N2) - static_cast<double>(N1) + 1);
}

int main()
{
    int Number;

    while (true)
    {
        cout << "Please enter integer number between 1 and 100: ";
        cin >> Number;

        // input check for consistency
        if (cin.fail() || (Number < 1) || (Number > 100))
        {
            std::cin.clear();
            std::cin.ignore(32767, '\n');
            cout << "Wrong input" << endl << endl;
            continue;
        }

        cout << fixed << setprecision(2);
        if (Number < 50)
            cout << "Average 1 -> " << Number << " is " << Average(1, Number);
        else
            cout << "Average " << Number << " -> 100 is " << Average(Number, 100);

        return 0;
    }    
}