Answer to Question #275038 in Computer Networks for mai

Question

Given the following host requirements and using the IP address 195. 20. 5.0/18 divide the network using VLSM. 550, 30, 1050, 880, 58, 2, 2, 2 

Answer 1

Given the following host requirements and using the IP address 195. 20. 5.0/18 divide the

network using VLSM. 550, 30, 1050, 880, 58, 2, 2, 2 

Answer:

Network host is an hardware device that communicates with other host on a network.

Subnetting table.

Subnet

1,2,4,8,16,32,64,128,256

Host

256,128,64,32,16,8,4,2,1

Subnet mask

/24,/25,/26,/27,/28,/29,/30,/31,/32

VSLM definition - Variable Length Subnet Mask (VLSM) is a subnet of larger network that is a design strategy where all subnet masks can have varying size VLSM allows you to use different subnet masks across the network for the same class of addresses. For example, a /30 subnet mask, which gives 2 host addresses per subnet.

Class              Range                          Mask

A                       0-126                             255.0.0.0

B                        128-191                        255.255.0.0

C                        192-223                          255.255.255.0

The above question fall under Class C of subnets.195.20.5.0/18

550 host

Its subnet mask is 255.255.255.0

Host IP address of 550 host using original IP address is  195.20.4.0 (4 is the subnet of 550 host network) (550 you break by 255+255+40 so 40 its subnet is 4 because 40 is more than 32).

30 Host

IP address of 30 host

192.20.16.0 (16 is the subnet of 30 host in subnetting table)

1050 Host

=255+255+255+30-(30 host is 16 subnets)