Answer to Question #216154 in Computer Networks for sisa

Question

For the given IP address with subnet, identify the number of subnet, the valid host IP addresses for the given problem. Network address : 200.10.10.0 Number of needed usable hosts : 20 Address Class : ---------------- Number of host bits borrowed : ------------------------------ Default Subnet mask : ----------- Custom subnet mask : ----------- Total number of subnets : ------------------------------- Total number of host addresses : ------------------------------- Number of usable address : ------------------------------- i. What is the 7 th subnet range? ii. What is the subnet number for the 5 th subnet? iii. What is the broadcast address of the 4 th subnet? iv. What are the assignable addresses for the 6 th subnet?

Answer 1

Address class will be C since the range of class C address is from 192.0.0.0 to 233.255.255.255

Number of host bits borrowed is 3; since we need 20 hosts. Hence Class C address has the fourth quad as the host address. If 3 host bits, were borrowed then there will be 5 zeros so that we can have 2 raised to the power of 5 which gives us 32 hosts for one sub net.

The default sub net mask is 255.255.255.0 as this is the default sub net mask for Class C addresses.

The custom sub net mask is 255.255.255.240 this is as a result of borrowing 3host bits i.e.( 128 + 64 + 32 = 240).

The total number of sub nets is 8 i.e. 2 raised to the power of borrowed host bits(3)which gives us 8 sub nets.

The total number of host addresses is 254 as this is a Class C address it allows a maximum of 256-2 = 254. The two addresses deducted represent the network address and and broadcast address each.

The number of usable addresses is 240. Since we have 8 sub nets each sub net having 32 addresses, we will deduct 2 addresses from each sub net so as to have 30 hosts, thus 30 * 8 gives us 240 assignable addresses.

1. The 7th sub net range is 200.10.10.160 - 200.10.10.191
2. The sub net number for the 5 the sub net is 200.10.10.128/127
3. The broadcast address of the 4 the sub net is 200.10.10.127 this is because the range of the fourth sub net lies between 200.10.10.96 -127. The last address in this 4th sub net range is the broadcasting address.
4. The assignable addresses for the 6 the sub net will be 200.10.10.161 - 200.10.10.10.190