Answer to Question #185886 in Computer Networks for muhammad rashid iqbal

Question

Mr. Hadi sent an email using 01 Gbps network bandwidth which contained a message size of 2.5-KB (Kilobyte) . Mr. John is X km away from sender (where X is last 3 digit of your arid number) who received email at speed of light travels at 2.4 × 108 m/s. You may need to calculate propagation time and the transmission time for the entire communication, and also discuss the dominant factor in this communication. Draw the figure by labelling all above mentioned values and add screen shot in your answer along with your solution.

Answer 1

Given,

Size of message = 2.5kb

Network bandwidth = 1Gbps

Distance between the sender and receiver (d)= 558 km

Propagation speed $= 2.4 \times 10^8 m/s$

Calculation of propagation time:

Propagation time = distance / propagation speed

$=\frac{ 558 \times 1000 m}{ 2.4 × 10^8 m/s}$

$=2.325\times 10^{-3} sec$

$=2.325msec$

Calculation of transmission time :

transmission time =message size / bandwidth

$=\frac{(2500)}{10^9} ms$

=0.020 ms

Here,

2.5kB =2.5×1000byte

1gbps = 10^9 bps