Question

#include<stdio.h>
int main()
{
int x=15;
printf("\n %d %d %d",x!=15,x=20,x<30);
return 0;
}
please explain the logic behind this program and give the output sir.

Answer 1

Solve
Output:

1 20 1
Explain:
In printf exist assignment to x, it execute first. So, at printf value of x is 20.
Since 20≠15, we have true value and as integer this expression have value 1
Since x=20, second output – is output x, so, we have 20
Since 20<30, we have true value and as integer this expression have value 1