Question

Suppose NAME is a 8 element array and 5 elements (Brown,Davis,Johnson,Smith,wagner)are in array observe that names are listed alphabetically and keep it alphabetical all times suppose ford and Taylor are added to the array and Davis removed from array

Answer 1

 #include <stdlib.h>
 #include <string.h>
 #include <stdio.h>
 #define n 8
 #define m 10
 
 int main()
 {
    char NAME[n][m] = {"Brown" ,"Davis", "Johnson", "Smith" ,"Wagner", "", "", ""};
    int i, j, cnt;
    cnt = 5;
    printf("-----source array-------\n");
    for (i=0; i<cnt; i++)
    {
       printf("%s\n", NAME[i]);
    }
    cnt++;
    strcpy(NAME[cnt-1], "Ford");
    cnt++;
    strcpy(NAME[cnt-1], "Taylor");
    printf("-----after Ford and Taylor are added------\n");
    for (i=0; i<cnt; i++)
    {
       printf("%s\n", NAME[i]);
    }
    qsort(NAME, cnt, sizeof(char[m]), (int (*)(const void *,const  void *)) strcmp);
    
    printf("-----sort array------\n");
    for (i=0; i<cnt; i++)
    {
       printf("%s\n", NAME[i]);
    }
    
    for (i=0; i<cnt; i++)
    {
       if (strcmp(NAME[i], "Davis") == 0)
       {
               for (j=(i+1); j<cnt; j++)
                   strcpy(NAME[j-1], NAME[j]);
               strcpy(NAME[j-1], "");
            break;
       }
    }
    
    printf("-----after Davis is removed------\n");
    for (i=0; i<cnt; i++)
    {
       printf("%s\n", NAME[i]);
    }
     
    return 0;
 }