Answer to Question #279525 in C for wohayez

Question

Make me a program that accepts a random string (a series of characters). Then, look for a digit from that string and if there's at least one, print out "That one!" but if there's none, print out "No one..."

I know this is too sudden to ask you, but thank you in advance!

Tip: After your scan for the size, add a space after the placeholder like this so that the newline character directly after the number won't be scanned as one of the characters:

scanf("%d ", &size);

Input

1. Size of the string

2. Characters of the string

Output

The first line will contain a message prompt to input the size of the string.

The second line will prompt for the characters of the string.

The last line contains the appropriate string.

Enter·the·size:·18
Enter·the·characters:·CodeChum1sAwesome!
That·one!

Answer 1

#include<studio.h>
include<string.h>
#include <stdlib.h>
int main()
{	int n ; 	
printf("Enter·the·size:  ");
	scanf("%d", n);	
	char name[n] ;	
printf("Enter·the·characters:  ");	
scanf("%s", &name);	
//	"CodeChum1sAwesome!";//	printf("%s", name);	
int len = strlen(name);
	int i ;	
for(i = 0; i<len; i++){	
	if(isdigit(name[i]) != 0){	
	
	printf("That·one!");		
}	
}	
	}