Answer to Question #275790 in C for Vicky

Question

Suppose you have a main() with three local arrays, all the same size and type (say

float). The first two are already initialized to values. Write a function called

addarrays() that accepts the addresses of the three arrays as arguments; adds the contents

of the first two arrays together, element by element; and places the results in the

third array before returning. A fourth argument to this function can carry the size of the

arrays. Use pointer notation throughout; the only place you need brackets is in defining

the arrays.

Answer 1

#include<iostream>
#include<string>

#define SIZE 10

using namespace std;

void addarrays(floatarr1[],float arr2[],float sum[],int n)
{
  int i;
  for (i=0;i<n;i++)
    sum[i]=arr1[i]+arr2[i];
}

int main()
{
  float arr1[SIZE]={1,2,3,4,5,6,7,8,9,0},
        arr2[SIZE]={3,2,1,5,2,3,4,5,0,1},
        arr3[SIZE];
  int n=SIZE,i;
  addarrays(arr1,arr2,arr3,n);
  cout<<"Array 1:";
  for(i=0;i<n;i++)
    cout<<arr1[i]<<"";
  cout<<endl<<"Array2:";
  for(i=0;i<n;i++)
    cout<<arr2[i]<<"";

  cout<<endl<<"Array3:";
  for(i=0;i<n;i++)
    cout<<arr3[i]<<"";

  return 0;
}