Question #275682

Given a square matrix of size N*N, print the sum of upper and lower triangular elements. Upper Triangle consists of elements on the diagonal and above it. The lower triangle consists of elements on the diagonal and below it.


Expert's answer



#include <stdio.h>


void calculateSum(int squareMatrix[3][3], int N)
{
	int i, j;
	int sumUpperTriangle = 0;
	int sumLowerTriangle = 0;


	//to calculate sum of upper triangle
	for (i = 0; i < N; i++){
		for (j = 0; j < N; j++) {
			if (i <= j) {
				sumUpperTriangle += squareMatrix[i][j];
			}
		}
	}
	//to calculate sum of lower triangle
	for (i = 0; i < N; i++){
		for (j = 0; j < N; j++) {
			if (j <= i) {
				sumLowerTriangle += squareMatrix[i][j];
			}
		}
	}
	printf("Upper triangle:\n");
	for (i = 0; i < N; i++){
		for (j = N-1; j >= 0; j--){
			if (i <= j) {
				printf("%d ",squareMatrix[i][j]);
			}
		}
		printf("\n");
	}
	printf("\nLower triangle:\n");
	for (i = 0; i < N; i++){
		for (j = 0; j < N; j++) {
			if (j <= i) {
				printf("%d ",squareMatrix[i][j]);
			}
		}
		printf("\n");
	}
	printf("\nThe sum of upper triangle is %d\n", sumUpperTriangle);
	printf("The sum of lower triangle is %d\n", sumLowerTriangle);
}


int main()
{
	const int N = 3;
	int squareMatrix[3][3] = {{ 7, 9, 4 },{ 2, 1, 2 },{ 8,8, 4 }};




	calculateSum(squareMatrix,N);


	getchar();
	getchar();
	return 0;
}
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