Answer to Question #269891 in C for Mau

Question

The placement session has begun in a college. There is N number of students standing outside an interview room in a line. It is given that the person who goes first has higher chances of selection.

Each student has a number associated with them representing their problem-solving capability. The higher the capability the higher the chances of selection. Now every student wants to know the number of students ahead of him with higher problem-solving capability.

Input: 6(number of students) {4 , 9 , 5 , 3 , 2 , 10}

Output: {0 , 0 , 1 , 3 , 4 , 0}

Answer 1

#include <stdio.h>


int main()
{
    int n;
    printf("\nEnter number of students: ");
    scanf("%d",&n);
    printf("\nEnter the capabilities of each student: ");
    int capability[n];
    
    for(int i=0;i<n;i++){
        scanf("%d",&capability[i]);
    }
    
    printf("0 ");
    
    for(int i=1;i<n;i++){
        int count =0;
        for(int j=1;j<i;j++){
            if (capability[j] >= capability[i]){
                count+=1;
            }
        }
        printf("%d ",count);
    }
    
    return 0;
}