Answer to Question #269298 in C for Neil

Question

Instructions:

1. Input a 3-digit integer.
2. Print the largest digit in the integer.
3. Tip #1: Use % 10 to get the rightmost digit. For example, if you do 412 % 10, then the result would be the rightmost digit, which is 2.
4. Tip #2: On the other hand, use / 10 to remove the rightmost digit. For example, if you do 412 / 10, then the result would be 41.
5. Tip #3: You'd have to repeat Tip #1 and Tip #2 three times for this problem because the input is a 3-digit integer.

Input

1. A three-digit integer

Output

The first line will contain a message prompt to input the 3-digit integer.

The last line contains the largest digit of the inputted integer.

Enter a 3-digit integer: 173
Largest = 7

Enter a 3-digit integer: 109
Largest = 9

Enter a 3-digit integer: 666
Largest = 6

Answer 1

#include <stdio.h>

int main()
{
    int x, lagest;
    printf("Enter a 3-digit integer: ");
    scanf("%d", &x);

    lagest = 0;
    if (x%10 > lagest) {
        lagest = x%10;
    }
    x = x / 10;
    if (x%10 > lagest) {
        lagest = x%10;
    }
    x = x / 10;
    if (x%10 > lagest) {
        lagest = x%10;
    }
    
    printf("Lagest = %d\n", lagest);

    return 0;
}