Answer to Question #264674 in C for Sofia

Question

Write a program to take as input the name, height in cm and age of n employees, and

sorts it according to height in descending order. If two employees have the same height, then it sorts

according to age in descending order. Print the employees in the sorted order.

Sample input:

5

Mr. Kamal

165 32

Ms. Zara

163 28

Nitu Roy

165 28

Rakib Hasan

178 25

Samira Haque

165 28

Sample output:

Rakib Hasan 178 25

Mr. Kamal 165 32

Nitu Roy 165 28

Samira Haque 165 28

Ms. Zara 163 28

Answer 1

#include <stdio.h>
#include <string>
#include <stdlib.h>


int main(){
	//array of N names, an array of N heights and an array of N ages
	char names[50][50];
	char tempName[50];
	int heights[50];
	int ages[50];
	int N,i,c, d, tempHeight,tempAge;
	printf("Enter N: ");
	scanf("%d",&N);


	for(i=0;i<N;i++){
		fflush(stdin);
		printf("Enter name %d: ",(i+1));
		gets(names[i]);
		printf("Enter heights %d: ",(i+1));
		scanf("%d",&heights[i]);
		printf("Enter age %d: ",(i+1));
		scanf("%d",&ages[i]);
	}


	for (c = 0 ; c < N - 1; c++)
	{
		for (d = 0 ; d < N - c - 1; d++)
		{
			if (heights[d] < heights[d+1])
			{


				strcpy(tempName,names[d]);
				strcpy(names[d],names[d+1]);
				strcpy(names[d+1],tempName);


				tempHeight   = heights[d];
				heights[d]   = heights[d+1];
				heights[d+1] = tempHeight;


				tempAge   = ages[d];
				ages[d]   = ages[d+1];
				ages[d+1] = tempAge;
			}else if (heights[d]== heights[d+1]){
				if (ages[d] < ages[d+1])
				{


					strcpy(tempName,names[d]);
					strcpy(names[d],names[d+1]);
					strcpy(names[d+1],tempName);


					tempHeight   = heights[d];
					heights[d]   = heights[d+1];
					heights[d+1] = tempHeight;


					tempAge   = ages[d];
					ages[d]   = ages[d+1];
					ages[d+1] = tempAge;
				}	
			}
		}
	}
	printf("\n%-15s%-15s%-15s\n","Names","Height","Age");
	for(i=0;i<N;i++){
		printf("%-15s%-15d%-15d\n",names[i],heights[i],ages[i]);
	}


	getchar();
	getchar();
	return 0;
}